5r^2=936

Solution for 5r^2=936 equation:

5r^2=936

We move all terms to the left:

5r^2-(936)=0

a = 5; b = 0; c = -936;
Δ = b2-4ac
Δ = 02-4·5·(-936)
Δ = 18720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18720}=\sqrt{144*130}=\sqrt{144}*\sqrt{130}=12\sqrt{130}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{130}}{2*5}=\frac{0-12\sqrt{130}}{10}
=-\frac{12\sqrt{130}}{10}
=-\frac{6\sqrt{130}}{5}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{130}}{2*5}=\frac{0+12\sqrt{130}}{10}
=\frac{12\sqrt{130}}{10}
=\frac{6\sqrt{130}}{5}
$